问题详情:
某公司需招聘一名员工,对应聘者*、乙、*从笔试、面试、体能三个方面进行量化考核,*、乙、*各项得分如下表:
笔试 | 面试 | 体能 | |
* | 83 | 79 | 90 |
乙 | 85 | 80 | 75 |
* | 80 | 90 | 73 |
(1)根据三项得分的平均分,从高到低确定三名应聘者的排名顺序.
(2)该公司规定:笔试,面试、体能得分分别不得低于80分,80分,70分,并按60%,30%,10%的比例计入总分,根据规定,请你说明谁将被录用.
【回答】
解:(1) =(83+79+90)÷3=84,
=(85+80+75)÷3=80,
=(80+90+73)÷3=81.············································································ 3分
从高到低确定三名应聘者的排名顺序为:*,*,乙;··································· 4分
(2)∵该公司规定:笔试,面试、体能得分分别不得低于80分,80分,70分,
∴*淘汰,···································································································· 5分
乙成绩=85×60%+80×30%+75×10%=82.5,······················································· 7分
*成绩=80×60%+90×30%+73×10%=82.3,····················································· 9分
∴乙将被录取. ························································································· 10分
知识点:数据的波动程度
题型:解答题